Functional-integral representation of the Kadyshevsky perturbation expansion
Establish that the Kadyshevsky perturbation expansion is generated by the functional integral expression given in equation (C.11), with the normalization chosen so that the generating functional satisfies Z[0,0,0]=1.
References
Then, the conjecture would be something like: The perturbation expansion in Kadyshevsky graphs is delivered by the functional
— Topics in Kadyshevsky Field Theory
(2609.03530 - Rijken et al., 3 Sep 2026) in Section Cc, equation (C.11)