Strictness of inclusions P ⊆ NP ⊆ PP ⊆ PSPACE
Determine whether each containment in the hierarchy P ⊆ NP ⊆ PP ⊆ PSPACE is strict; specifically, prove or refute the equalities P = NP, NP = PP, and PP = PSPACE.
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References
Each inclusion is known to hold (provably). None of the inclusions is known to be strict, but we have strong evidence that they are.
— From Heisenberg and Schrödinger to the P vs. NP Problem
(2511.07502 - Weinstein, 10 Nov 2025) in Subsection 4.3. The White Raven and a Needle in the Haystack, Footnote labeled “class”