- The paper proves that for every k ≥ 5 and bipartite H, only finitely many k-vertex-critical (P₅,H)-free graphs exist exactly when H is 2P₂-free, using prime-graph reductions and unavoidable induced subgraphs.
- The paper resolves the outstanding cases H = P₄ + P₁ and H = C₄ + P₁, extends finiteness to forbidden graphs of the form Kₛ,ₜ + e, and establishes new finite and infinite families for non-bipartite obstructions.
- The results support polynomial-time certifying k-Colouring algorithms in the finite cases while leaving major questions open for higher-chromatic H, including K₅ − e, K₅, and the Cameron–Hoàng–Sawada conjecture.
This paper by Beaton and Cameron (2608.20045) establishes a complete finiteness dichotomy for k-vertex-critical (P5,H)-free graphs when H is bipartite, and contributes several new positive and negative results toward two long-standing open problems on vertex-critical graphs in hereditary classes. The central tool is the theorem of Chudnovsky, Kim, Oum, and Seymour on unavoidable induced subgraphs in large prime graphs.
Background and motivation
A graph is k-vertex-critical if χ(G)=k but every proper induced subgraph has chromatic number less than k. If a hereditary class contains only finitely many (k+1)-vertex-critical graphs, then k-Colouring restricted to that class admits a polynomial-time certifying algorithm: a "yes" certificate is a colouring and a "no" certificate is an induced (k+1)-vertex-critical subgraph. This motivates determining for which forbidden induced subgraphs H the quantity (P5,H)0 — the number of (P5,H)1-vertex-critical (P5,H)2-free graphs — is finite.
Two problems drive the paper. The first is the conjecture of Cameron, Hoàng, and Sawada that for (P5,H)3, there are finitely many (P5,H)4-vertex-critical (P5,H)5-free graphs if and only if (P5,H)6 is an induced subgraph of (P5,H)7 for some (P5,H)8. The second is the question of K. Cameron, Goedgebeur, Huang, and Shi asking for which graphs (P5,H)9 of order 5 there are finitely many H0-vertex-critical H1-free graphs for all H2. Prior to this work, five graphs of order 5 remained unresolved: H3, H4, H5, H6, and H7.
The prime graph framework
The paper's main proof technique rests on a reduction to prime graphs. The authors prove (via induction on H8, using the fact that homogeneous sets in a H9-vertex-critical graph induce k0-vertex-critical graphs for k1) that if the order of every k2-colourable prime graph in a hereditary class is bounded, then the class contains only finitely many k3-vertex-critical graphs. Combined with the unavoidable-subgraph theorem of Chudnovsky et al., this yields a corollary: for any k4 and k5, only finitely many prime graphs avoid all of k6, k7, k8, k9, and χ(G)=k0. A short lemma shows that any chain of length at least χ(G)=k1 contains an induced χ(G)=k2 or an induced χ(G)=k3, which eliminates the "chain" case from the unavoidable list.
The bipartite dichotomy
The key structural observation is that χ(G)=k4, χ(G)=k5, and χ(G)=k6 each contain an induced χ(G)=k7, while the half-graph χ(G)=k8 contains induced copies of both χ(G)=k9 and k0. Consequently:
- For all k1, there are finitely many k2-vertex-critical k3-free graphs.
- For all k4, there are finitely many k5-vertex-critical k6-free and k7-free graphs. The cases k8 resolve two of the five outstanding instances of the order-5 problem, namely k9 and (k+1)0.
The main theorem then follows from the fact that (k+1)1 is universal for (k+1)2-free bipartite graphs (Lozin and Rudolf): for bipartite (k+1)3 and any (k+1)4, there are finitely many (k+1)5-vertex-critical (k+1)6-free graphs if and only if (k+1)7 is (k+1)8-free. The necessity direction uses the known infinitude of (k+1)9-vertex-critical k0-free graphs for k1; the sufficiency direction embeds any k2-free bipartite k3 into a sufficiently large half-graph via a nested-neighbourhood argument. This is the largest subfamily of k4-free graphs for which finiteness of k5-vertex-critical graphs has been established, and it generalizes prior results for k6 being complete bipartite, banner, k7, k8, or chair.
Non-bipartite k9: finiteness and infinitude
Toward the natural refinement — for which (k+1)0 with (k+1)1 is (k+1)2 finite for all (k+1)3? — the paper proves two complementary types of results.
On the positive side, for all (k+1)4 and (k+1)5, there are finitely many (k+1)6-vertex-critical (k+1)7-free graphs, where (k+1)8 is a complete bipartite graph plus one edge within one part. The proof assumes a large induced half-graph exists in a critical graph, uses Lemma on anticomplete pairs to extract vertices with controlled adjacency to the half-graph, applies a Ramsey argument (k+1)9 to obtain a stable set of size H0, and derives an induced H1 — a contradiction. This generalizes earlier finiteness results for H2, H3, and cricket.
On the negative side, the authors analyze the circulant-style graphs H4 of Cameron and Hoàng, which are H5-vertex-critical, H6-free, and H7-free. New structural lemmas show that the smallest hole in H8 has length at least H9 (each residue class modulo (P5,H)00 must appear on any cycle of length at least 4 in the complement), and that (P5,H)01 is net-free and co-net-free. Hence for all (P5,H)02 there are infinitely many (P5,H)03-vertex-critical (P5,H)04-free graphs when (P5,H)05 is net, co-net, or (P5,H)06 for (P5,H)07. Via the Strong Perfect Graph Theorem, the last result implies that any (P5,H)08 satisfying the chromatic-number-refined problem must be perfect.
For the (P5,H)09-free setting, the same prime-graph framework yields finiteness of (P5,H)10-vertex-critical (P5,H)11-free graphs for all (P5,H)12 — the largest known such subfamily, and further evidence for the Cameron–Hoàng–Sawada conjecture, which remains open even for (P5,H)13, (P5,H)14.
Computational results for (P5,H)15-containing obstructions
Since any (P5,H)16 satisfying the refined problem must contain a triangle but no (P5,H)17 (as (P5,H)18 for (P5,H)19 while finite for (P5,H)20), the authors examine the four (P5,H)21-free order-6 graphs containing an induced (P5,H)22. They show (P5,H)23 is (P5,H)24-free and (P5,H)25-free, so these do not obstruct finiteness. Exhaustive generation using Jooken's program gives exact counts:
| Forbidden (P5,H)26 |
Number of 5-vertex-critical (P5,H)27-free graphs |
| twin-(P5,H)28 |
287 |
| (P5,H)29 |
188 |
These lists are publicly available in graph6 format. Based on this evidence, the authors conjecture that for (P5,H)30, finiteness holds exactly when (P5,H)31 is (P5,H)32-free.
Limitations and open questions
Several questions remain explicitly open. The remaining three cases of the order-5 problem ((P5,H)33, (P5,H)34, (P5,H)35) all have chromatic number at least 4, and the only 4-chromatic (P5,H)36 for which finiteness is known is (P5,H)37. The Cameron–Hoàng–Sawada conjecture is unresolved even in its most restrictive nontrivial instance. It is also open whether (P5,H)38 is finite when (P5,H)39 contains an induced (P5,H)40. The finiteness results here establish existence of polynomial-time certifying algorithms but do not provide explicit bounds on the number or size of critical graphs beyond finiteness itself, and the computational counts cover only (P5,H)41.
Conclusion
The paper delivers a clean dichotomy for bipartite (P5,H)42 — finiteness holds precisely when (P5,H)43 is (P5,H)44-free — resolves two outstanding cases of the order-5 problem, extends finiteness to all graphs (P5,H)45, and demonstrates infinitude for net, co-net, and complements of short cycles. Methodologically, it demonstrates that building arguments around arbitrarily large induced half-graphs (and, analogously, (P5,H)46) is a viable template for bounding vertex-critical graphs in other hereditary classes, complementing earlier techniques based on large induced (P5,H)47.