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Quantized Volume Comparison for Fano Manifolds, II

Published 18 Aug 2026 in math.AG and math.DG | (2608.17397v1)

Abstract: In this note, the second author's quantized volume comparison conjecture is solved: If XX is a smooth complex KK-semistable Fano variety of dimension nn, then for every integer m1m\geq1, [ h0(X,-mK_X)\leq h0(\mathbb Pn,-mK_{\mathbb Pn}) =\binom{n+m(n+1)}{n}, ] and equality for one mm characterizes projective space. Somewhat surprisingly, the same statement actually holds whenever TXT_X is slope semistable with respect to KX-K_X. The idea is to apply a jet-dimension counting trick to a filtration of subsheaves induced by H<sup>0(X,mKX)H<sup>0(X,-mK_X). Then the slope semistability condition yields the desired dimension bound.

Authors (2)

Summary

  • The paper proves that every smooth Fano n-fold with slope-semistable tangent bundle satisfies h⁰(X,−mK_X) ≤ binom(n+m(n+1), n) for all m≥1, with equality at one level forcing X ≅ ℙⁿ.
  • The authors combine a jet-filtration slope bound with sharp weighted jet counting, converting semistability of symmetric powers of the cotangent bundle into finite-level Hilbert function estimates.
  • The result implies the sharp volume bound (−K_X)ⁿ ≤ (n+1)ⁿ under tangent-bundle slope semistability and extends to polarized varieties, pseudoeffective line bundles, and ℚ-Fano varieties.

Overview and main results

This paper by Lyu and Zhang resolves the quantized volume comparison conjecture formulated by the second author in earlier work. The conjecture asks for a finite-level refinement of Fujita's volume comparison: if XX is a smooth complex KK-semistable Fano nn-fold, Fujita proved (KX)n(n+1)n(-K_X)^n \le (n+1)^n with equality only for Pn\mathbb P^n, and since h0(X,mKX)=(KX)nn!mn+O(mn1)h^0(X,-mK_X) = \frac{(-K_X)^n}{n!}m^n + O(m^{n-1}), it is natural to ask whether the comparison holds level by level. The paper proves that for every m1m \ge 1,

h0(X,mKX)h0(Pn,mKPn)=(n+m(n+1)n),h^0(X,-mK_X) \le h^0(\mathbb P^n,-mK_{\mathbb P^n}) = \binom{n+m(n+1)}{n},

with equality at a single value of mm forcing XPnX \simeq \mathbb P^n. The notable strengthening is that the same statement holds under the strictly weaker hypothesis that the tangent bundle KK0 is slope semistable with respect to KK1; KK2-semistability enters only via Li's extension of Tian's theorem, which produces this semistability. The result also yields, as a corollary, the Fujita–Liu volume bound KK3 under slope semistability alone — a sharp estimate that, according to the authors, had not previously been recorded under this hypothesis. Ran had earlier obtained only the non-sharp bound KK4 under the same semistability assumption plus additional hypotheses.

Context: Yau's conjecture and prior work

The conjecture is the compact analogue of Yau's conjecture for complete noncompact Kähler manifolds KK5 with nonnegative holomorphic bisectional curvature: KK6, with equality only for KK7. That statement was proved by Ni under maximal volume growth, in full generality with rigidity by Chen–Fu–Yin–Zhu, and strengthened by Liu, who replaced bisectional curvature with the weaker nonnegative holomorphic sectional curvature using his three-circle theorem. The paper notes a precise structural parallel: with KK8, the Euclidean model dimension KK9 coincides with the Fano comparison term, so both results are sharp jet-counting statements with model-space rigidity, differing in the nature of the hypotheses (pointwise curvature versus algebraic slope semistability).

In the predecessor paper, the second author proved the comparison for all sufficiently large nn0, and conditionally in dimension four. The present work removes both restrictions.

The proof mechanism

The argument combines two ingredients, neither of which uses the valuative criterion for K-stability directly.

Jet-filtration slope bound. For nn1 with nn2, nn3, the kernels of the evaluation maps nn4 into sheaves of principal parts form a decreasing filtration nn5. The nn6-th graded image nn7 is a torsion-free subsheaf of nn8. Since nn9 is (KX)n(n+1)n(-K_X)^n \le (n+1)^n0-semistable, so is (KX)n(n+1)n(-K_X)^n \le (n+1)^n1, and hence each (KX)n(n+1)n(-K_X)^n \le (n+1)^n2 is semistable with slope (KX)n(n+1)n(-K_X)^n \le (n+1)^n3 — this uses the Mehta–Ramanathan restriction to general complete-intersection curves, the characteristic-zero tensor product theorem, and the symmetrizing idempotent. Summing the slope inequalities (KX)n(n+1)n(-K_X)^n \le (n+1)^n4 over the filtration and using the telescoping identity (KX)n(n+1)n(-K_X)^n \le (n+1)^n5 (which follows from termination of the filtration via Krull intersection and finite-dimensionality of (KX)n(n+1)n(-K_X)^n \le (n+1)^n6) yields, for general (KX)n(n+1)n(-K_X)^n \le (n+1)^n7,

(KX)n(n+1)n(-K_X)^n \le (n+1)^n8

Sharp jet counting. Conversely, a Taylor-expansion (hockey-stick) estimate shows that if (KX)n(n+1)n(-K_X)^n \le (n+1)^n9 with Pn\mathbb P^n0, then the weighted jet sum Pn\mathbb P^n1 strictly exceeds Pn\mathbb P^n2 — a contradiction. Hence Pn\mathbb P^n3.

Equality case. If Pn\mathbb P^n4 attains the bound, equality forces the order-Pn\mathbb P^n5 jet evaluation map Pn\mathbb P^n6 to be an isomorphism, so Pn\mathbb P^n7 generates Pn\mathbb P^n8 jets at Pn\mathbb P^n9, whence h0(X,mKX)=(KX)nn!mn+O(mn1)h^0(X,-mK_X) = \frac{(-K_X)^n}{n!}m^n + O(m^{n-1})0. The Bauer–Szemberg characterization of projective space by anticanonical Seshadri constants then gives h0(X,mKX)=(KX)nn!mn+O(mn1)h^0(X,-mK_X) = \frac{(-K_X)^n}{n!}m^n + O(m^{n-1})1. This is a rigidity statement at a single finite level h0(X,mKX)=(KX)nn!mn+O(mn1)h^0(X,-mK_X) = \frac{(-K_X)^n}{n!}m^n + O(m^{n-1})2, which is stronger than what asymptotic methods provide.

Generalizations

The core theorem is stated for an arbitrary polarization h0(X,mKX)=(KX)nn!mn+O(mn1)h^0(X,-mK_X) = \frac{(-K_X)^n}{n!}m^n + O(m^{n-1})3 and line bundle h0(X,mKX)=(KX)nn!mn+O(mn1)h^0(X,-mK_X) = \frac{(-K_X)^n}{n!}m^n + O(m^{n-1})4: if h0(X,mKX)=(KX)nn!mn+O(mn1)h^0(X,-mK_X) = \frac{(-K_X)^n}{n!}m^n + O(m^{n-1})5 is h0(X,mKX)=(KX)nn!mn+O(mn1)h^0(X,-mK_X) = \frac{(-K_X)^n}{n!}m^n + O(m^{n-1})6-semistable and h0(X,mKX)=(KX)nn!mn+O(mn1)h^0(X,-mK_X) = \frac{(-K_X)^n}{n!}m^n + O(m^{n-1})7, then

h0(X,mKX)=(KX)nn!mn+O(mn1)h^0(X,-mK_X) = \frac{(-K_X)^n}{n!}m^n + O(m^{n-1})8

and, for pseudoeffective h0(X,mKX)=(KX)nn!mn+O(mn1)h^0(X,-mK_X) = \frac{(-K_X)^n}{n!}m^n + O(m^{n-1})9 with m1m \ge 10, one obtains m1m \ge 11. The anticanonical result follows by taking m1m \ge 12. A final remark extends the argument to m1m \ge 13-semistable m1m \ge 14-Fano varieties via reflexive sheaves on the regular locus; codimension-one regularity ensures that reflexive extension does not affect slopes, and the singular Seshadri characterization of Liu–Zhuang handles equality. The extension to m1m \ge 15-Fano varieties includes levels m1m \ge 16 for which m1m \ge 17 is not Cartier.

Limitations and open questions

The paper is explicit about what its method does not deliver. First, it does not recover the earlier fixed-level result conditional on m1m \ge 18: the present filtration controls the ordinary vanishing-order filtration at a general point, whereas m1m \ge 19 is an infimum over all valuations, and the argument does not deduce the finite-level delta invariant from h0(X,mKX)h0(Pn,mKPn)=(n+m(n+1)n),h^0(X,-mK_X) \le h^0(\mathbb P^n,-mK_{\mathbb P^n}) = \binom{n+m(n+1)}{n},0-semistability. Second, and more significantly, finite-level rigidity does not imply volume rigidity: equality of volumes fixes only the leading coefficient of the anticanonical Hilbert polynomial and is compatible with a strict h0(X,mKX)h0(Pn,mKPn)=(n+m(n+1)n),h^0(X,-mK_X) \le h^0(\mathbb P^n,-mK_{\mathbb P^n}) = \binom{n+m(n+1)}{n},1 deficit at every finite level. The authors accordingly leave open whether a smooth Fano h0(X,mKX)h0(Pn,mKPn)=(n+m(n+1)n),h^0(X,-mK_X) \le h^0(\mathbb P^n,-mK_{\mathbb P^n}) = \binom{n+m(n+1)}{n},2-fold with h0(X,mKX)h0(Pn,mKPn)=(n+m(n+1)n),h^0(X,-mK_X) \le h^0(\mathbb P^n,-mK_{\mathbb P^n}) = \binom{n+m(n+1)}{n},3-semistable h0(X,mKX)h0(Pn,mKPn)=(n+m(n+1)n),h^0(X,-mK_X) \le h^0(\mathbb P^n,-mK_{\mathbb P^n}) = \binom{n+m(n+1)}{n},4 and h0(X,mKX)h0(Pn,mKPn)=(n+m(n+1)n),h^0(X,-mK_X) \le h^0(\mathbb P^n,-mK_{\mathbb P^n}) = \binom{n+m(n+1)}{n},5 must be h0(X,mKX)h0(Pn,mKPn)=(n+m(n+1)n),h^0(X,-mK_X) \le h^0(\mathbb P^n,-mK_{\mathbb P^n}) = \binom{n+m(n+1)}{n},6; under h0(X,mKX)h0(Pn,mKPn)=(n+m(n+1)n),h^0(X,-mK_X) \le h^0(\mathbb P^n,-mK_{\mathbb P^n}) = \binom{n+m(n+1)}{n},7-semistability the answer is affirmative by Fujita's equality theorem.

A further point of context is the declaration on the use of AI: the jet-filtration slope bound, one of the two central ingredients, is credited to ChatGPT 5.6, likely building on Ran's work on sheaves of differential operators; the authors disclaim credit for that lemma while taking responsibility for the content.

Conclusion

The paper settles the quantized volume comparison conjecture in full, and in a stronger form than conjectured: sharp finite-level Hilbert function bounds and single-level rigidity hold for Fano manifolds whose tangent bundle is merely slope semistable, with h0(X,mKX)h0(Pn,mKPn)=(n+m(n+1)n),h^0(X,-mK_X) \le h^0(\mathbb P^n,-mK_{\mathbb P^n}) = \binom{n+m(n+1)}{n},8-semistability used only through Li's theorem. The method — a jet filtration graded into semistable symmetric powers of the cotangent sheaf, combined with sharp jet counting at a general point — is purely algebraic and adapts to polarized pairs, general line bundles, and h0(X,mKX)h0(Pn,mKPn)=(n+m(n+1)n),h^0(X,-mK_X) \le h^0(\mathbb P^n,-mK_{\mathbb P^n}) = \binom{n+m(n+1)}{n},9-Fano varieties. The main open problem left by the work is whether volume equality mm0 alone forces projective space under tangent-bundle semistability.

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