A "power" conjugate equation in the symmetric group
Abstract: First we consider the solutions of the general "cubic" equation a_{1}x{r1}a_{2}x{r2}a_{3}x{r3}=1 (with r1,r2,r3 in {1,-1}) in the symmetric group S_{n}. In certain cases this equation can be rewritten as aya{-1}=y{2} or as aya{-1}=y{-2}, where a in S_{n} depends on the a_{i}'s and the new unknown permutation y in S_{n} is a product of x (or x{-1}) and one of the permutations a_{i}{1} and a_{i}{-1}. Using combinatorial arguments and some basic number theoretical facts, we obtain results about the solutions of the so-called power conjugate equation aya{-1}=y{e} in S_{n}, where e is an integer exponent. Under certain conditions, the solutions are exactly the solutions of y{e-1}=1 in the centralizer of a.
Paper Prompts
Sign up for free to create and run prompts on this paper using GPT-5.
Top Community Prompts
Collections
Sign up for free to add this paper to one or more collections.