Papers
Topics
Authors
Recent
Gemini 2.5 Flash
Gemini 2.5 Flash
92 tokens/sec
Gemini 2.5 Pro Premium
51 tokens/sec
GPT-5 Medium
24 tokens/sec
GPT-5 High Premium
17 tokens/sec
GPT-4o
97 tokens/sec
DeepSeek R1 via Azure Premium
92 tokens/sec
GPT OSS 120B via Groq Premium
458 tokens/sec
Kimi K2 via Groq Premium
222 tokens/sec
2000 character limit reached

Asymptotics of Moore exponent sets (1907.11100v2)

Published 25 Jul 2019 in math.CO

Abstract: Let $n$ be a positive integer and $I$ a $k$-subset of integers in $[0,n-1]$. Given a $k$-tuple $A=(\alpha_0, \cdots, \alpha_{k-1})\in \mathbb{F}k_{qn}$, let $M_{A,I}$ denote the matrix $(\alpha_i{qj})$ with $0\leq i\leq k-1$ and $j\in I$. When $I={0,1,\cdots, k-1}$, $M_{A,I}$ is called a Moore matrix which was introduced by E. H. Moore in 1896. It is well known that the determinant of a Moore matrix equals $0$ if and only if $\alpha_0,\cdots, \alpha_{k-1}$ are $\mathbb{F}_q$-linearly dependent. We call $I$ that satisfies this property a Moore exponent set. In fact, Moore exponent sets are equivalent to maximum rank-distance (MRD) code with maximum left and right idealisers over finite fields. It is already known that $I={0,\cdots, k-1}$ is not the unique Moore exponent set, for instance, (generalized) Delsarte-Gabidulin codes and the MRD codes recently discovered by Csajb\'ok, Marino, Polverino and the second author both give rise to new Moore exponent sets. By using algebraic geometry approach, we obtain an asymptotic classification result: for $q>5$, if $I$ is not an arithmetic progression, then there exist an integer $N$ depending on $I$ such that $I$ is not a Moore exponent set provided that $n>N$.

Summary

We haven't generated a summary for this paper yet.

Dice Question Streamline Icon: https://streamlinehq.com

Follow-up Questions

We haven't generated follow-up questions for this paper yet.