Papers
Topics
Authors
Recent
Assistant
AI Research Assistant
Well-researched responses based on relevant abstracts and paper content.
Custom Instructions Pro
Preferences or requirements that you'd like Emergent Mind to consider when generating responses.
Gemini 2.5 Flash
Gemini 2.5 Flash 79 tok/s
Gemini 2.5 Pro 41 tok/s Pro
GPT-5 Medium 25 tok/s Pro
GPT-5 High 23 tok/s Pro
GPT-4o 99 tok/s Pro
Kimi K2 199 tok/s Pro
GPT OSS 120B 444 tok/s Pro
Claude Sonnet 4 36 tok/s Pro
2000 character limit reached

Charmless Hadronic B Decays into a Tensor Meson (1010.3309v2)

Published 16 Oct 2010 in hep-ph and hep-ex

Abstract: Two-body charmless hadronic B decays involving a tensor meson in the final state are studied within the framework of QCD factorization (QCDF). Due to the G-parity of the tensor meson, both the chiral-even and chiral-odd two-parton light-cone distribution amplitudes of the tensor meson are antisymmetric under the interchange of momentum fractions of the quark and anti-quark in the SU(3) limit. Our main results are: (i) In the naive factorization approach, the decays such as $B-\to \bar K_2{*0}\pi-$ and $\bar B0\to K_2{*-}\pi+$ with a tensor meson emitted are prohibited owing to the fact that a tensor meson cannot be created from the local V-A or tensor current. Nevertheless, they receive nonfactorizable contributions in QCDF from vertex, penguin and hard spectator corrections. The experimental observation of $B-\to \bar K_2{*0}\pi-$ indicates the importance of nonfactorizable effects. (ii) For penguin-dominated $B\to TP$ and $TV$ decays, the predicted rates in naive factorization are usually too small by one to two orders of magnitude. In QCDF, they are enhanced by power corrections from penguin annihilation and nonfactorizable contributions.(iii) The dominant penguin contributions to $B\to K_2*\eta{(')}$ arise from the processes: (a) $b\to ss\bar s\to s\eta_s$ and (b) $b\to s q\bar q\to q \bar K_2*$ with $\eta_q=(u\bar u+d\bar d)/\sqrt{2}$ and $\eta_s=s\bar s$. The interference, constructive for $K_2*\eta'$ and destructive for $K_2*\eta$, explains why $\Gamma(B\to K_2*\eta')\gg\Gamma(B\to K_2*\eta)$.

Summary

We haven't generated a summary for this paper yet.

Lightbulb Streamline Icon: https://streamlinehq.com

Continue Learning

We haven't generated follow-up questions for this paper yet.

List To Do Tasks Checklist Streamline Icon: https://streamlinehq.com

Collections

Sign up for free to add this paper to one or more collections.

Don't miss out on important new AI/ML research

See which papers are being discussed right now on X, Reddit, and more:

“Emergent Mind helps me see which AI papers have caught fire online.”

Philip

Philip

Creator, AI Explained on YouTube