Vertex-count congruence for all-rich snark covers
Prove that if a snark has a 6-cycle 4-cover with all edges rich, then its number of vertices is congruent to 2 modulo 4.
References
If we have a 6c4c solution for a snark with all rich edges, then the number of vertices is $4k+2$.
— Computational Graph Decompositions I: Oriented Berge-Fulkerson Conjecture
(2501.05348 - Ulyanov, 9 Jan 2025) in Section “More conjectures”