Rigidity Conjecture for the Hexablock Automorphism Group
Establish that G(ℍ) equals Aut(ℍ), where G(ℍ) is the subgroup of automorphisms of the hexablock ℍ consisting precisely of the maps T_{ν,χ,ω}(a,x) and T_{ν,χ,F,ω}(a,x) defined by T_{ν,χ,ω}(a,x) = ( ω ξ₂ a √[(1−|z₁|²)(1−|z₂|²)] / (1 − x₁ z̄₁ − x₂ z̄₂ ξ₂ + x₃ z̄₁ z̄₂ ξ₂), τ_{ν,χ}(x) ) and T_{ν,χ,F,ω}(a,x) = ( ω ξ₂ a √[(1−|z₁|²)(1−|z₂|²)] / (1 − x₁ z̄₁ − x₂ z̄₂ ξ₂ + x₃ z̄₁ z̄₂ ξ₂), τ_{ν,χ,F}(x) ), with x=(x₁,x₂,x₃)∈ℰ, ν=−ξ₁ B_{z₁}, χ=−ξ₂ B_{−z̄₂}, B_α(λ)=(λ−α)/(ᾱ λ−1), z₁,z₂∈𝔻, ξ₁,ξ₂∈𝕋, ω∈𝕋, and τ_{ν,χ}, τ_{ν,χ,F}∈Aut(ℰ); here ℍ⊂ℂ⁴ is the hexablock Hartogs domain over the tetrablock ℰ defined by {(a,x)∈ℂ×ℰ : sup_{z₁,z₂∈𝔻} |Ψ_{z₁,z₂}(a,x)| < 1}.
References
In their foundational work on the hexablock, Biswas-Pal-Tomar formulated the fundamental rigidity conjecture: $G(\mathbb{H}) = \mathrm{Aut}(\mathbb{H})$.