Equality of Euler excess and skewness for complete graphs of order divisible by six
Prove that for every integer m ≥ 1, every complete graph K_{6m}, and every orientable surface S_t with −1 ≤ t ≤ 2m² − 3m + 1, the t-excess δ_t(K_{6m}) equals the t-skewness μ_t(K_{6m}).
References
Conjecture 1. If n = 6m for m ≥ 1, then δt(Kn) = μt(Kn) for m − 1 ≤ t ≤ 2m2 − 3m + 1.
— Skewness, crossing number and Euler's bound for graphs on surfaces
(2501.02400 - Kainen, 4 Jan 2025) in Conjecture 1, Section 4, p. 9