Closure of d‑DNNF under complementation
Prove or refute that the class of deterministic decomposable negation normal form (d‑DNNF) circuits is closed under Boolean complementation.
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References
One obvious question is whether $\times,\uplus,$-circuits are more concise than $\times,\uplus$-circuits, which relates to the open problem of whether d-DNNFs are closed under complementation (see).
— On the Complexity of Language Membership for Probabilistic Words
(2510.08127 - Amarilli et al., 9 Oct 2025) in Section 7, Conclusion and Future Work