Boundary behavior of D0 in the Falkner–Skan adjoint expansion
Prove that the function D0(η) defined by D0(η) = Σk (2k + β − 1) Dk(η) satisfies the boundary conditions D0(0) = 1 and limη→∞ D0(η) = 0 for the Falkner–Skan boundary layer, thereby establishing from the series representation (equation (119)) that the analytic adjoint solution obeys the required adjoint boundary conditions.
References
The reason (which also explains the behavior of the solution that will be illustrated below by explicit evaluation of eq. (118)) is that, unlike the Blasius case, the function Do(n)=>- 00 k=1 2k + B-1. Dk (n) (119) is not constant but rather has to obey the equation -Do,nnn + FBDk.nn + (2-2 +2B) FB. Dk.n +(2+23-22k) FB.m.Dk =0 with boundary conditions Do(0) =1 and Do(o)=0, neither of which have we been able to prove directly from eq. (119).