Papers
Topics
Authors
Recent
Search
2000 character limit reached

PINNing the pion: conformal deep learning for Fπ(s)F_π(s) and the (g−2)μ(g-2)_μ hadronic contribution

Published 30 Sep 2026 in hep-ph, cs.LG, and hep-ex | (2609.40008v1)

Abstract: Extracting the pion electromagnetic form factor Fπ(s)F_π(s) through phenomenological curve-fitting models introduces model dependence, unphysical artefacts, and kinematic inconsistencies. We introduce a Physics-Informed Neural Network (PINN) embedded in a conformal zz-plane that constructs Fπ(s)F_π(s) directly from first principles across spacelike and timelike domains: charge normalisation and Schwarz reflection are enforced by construction, while Cauchy-Riemann analyticity, dispersion relations, Watson's theorem, and perturbative QCD asymptotics enter through the loss functional. Thus, the fundamental S-matrix principles dictate the form factor's behaviour while data act as constraints. Mapping the cut complex plane onto the unit disk bounds the Hessian norm and prevents Neural Tangent Kernel spectral starvation, two known failure modes of deep-learning optimisation. Besides e<sup>+e<sup>−e<sup>+e<sup>- scattering data, we also incorporate ττ-decay data through a switch that isolates the pure isovector form factor natively, bypassing model-dependent isospin-breaking pre-corrections. The network organically yields an interior zero-free form factor, while the framework tests experimental tensions around the ρ(770)ρ(770) peak against analyticity and dispersion constraints. We obtain model-independent estimates of the pion charge radius, ⟨rπ<sup>2</sup>⟩=0.435±0.008stat±0.007cali\langle r_π<sup>2</sup> \rangle = 0.435 \pm 0.008_{\text{stat}} \pm 0.007_{\text{cali}} fm<sup>2<sup>2, the second-sheet pole parameters, mρ<sup>pole</sup>=761.72±1.04m_ρ<sup>{\text{pole}}</sup> = 761.72\pm 1.04 MeV and Γ<em>ρ<sup>pole</sup>=135.99±1.20Γ<em>ρ<sup>{\text{pole}}</sup> = 135.99 \pm 1.20 MeV, and the two-pion contribution to the muon anomalous magnetic moment, a</em>μ<sup>ππ</sup>=(506.48±2.02stat±1.70cali)×10<sup>−10a</em>μ<sup>{ππ}</sup> = (506.48 \pm 2.02_{\text{stat}} \pm 1.70_{\text{cali}}) \times 10<sup>{-10}.

Summary

No one has generated a summary of this paper yet.

Paper to Video (Beta)

No one has generated a video about this paper yet.

Whiteboard

No one has generated a whiteboard explanation for this paper yet.

Continue Learning

We haven't generated follow-up questions for this paper yet.

Tweets

Sign up for free to view the 1 tweet with 2 likes about this paper.