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Curvature integral, volume ratio, bi-Lipschitz for spaces with curvature bounded below

Published 24 Sep 2026 in math.DG and math.MG | (2609.29982v1)

Abstract: By the paper \cite{Pet2009upper}, \cite{LiNan2026}, we know that there exists $C(n)>0$, for any complete compact or non-compact Riemannian n manifold MM with non-negative sectional curvature, without boundary and any $R>0$, \begin{equation} R{2-n}\int_{B(p,R)} Scal \le C(n). \end{equation} Based on this result, we will prove that (1) There exists constant C(n)C(n). If MM is a complete, n dimensional, non-compact Riemannian manifold with non-negative sectional curvature, then for any p∈Mp\in M, $R>0$, \begin{equation} R{2-n}\int_{B(p,R)} Scal \ dvol \le C(n)(1-v(M)), \end{equation} where ScalScal is the scalar curvature and v(M)=lim⁡R→∞volB(p,R)volB(0,R)v(M)=\lim\limits_{R\to \infty} \frac{volB(p,R)}{volB(0,R)} is the asymptotic volume ratio. (2) There exists constant C(n)C(n). If MM is a complete, n dimensional Riemannian manifold with sectional curvature ≥1\ge 1, then \begin{equation} \int_M (Scal-n(n-1)) \ dvol \le C(n)(1-\frac{vol(M)}{vol(Sn(1))}). \end{equation}

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