Papers
Topics
Authors
Recent
Search
2000 character limit reached

Pairings of combinatorial 1-cocycles with loops in knot spaces

Published 24 Sep 2026 in math.GT | (2609.29946v1)

Abstract: We show that the evaluations of combinatorial 1-cocycles defined by Gauss diagrams with a triangle on the canonical loops in the space of long knots are finite type invariants. Using Gauss diagrams, we construct two Z\mathbb{Z}-valued combinatorial 1-cocycles β1,β2β_1, β_2 and a Z/2Z\mathbb{Z}/2\mathbb{Z}-valued 1-cocycle β3β_3 on the space of long knots and prove their cocyclicity by verifying their invariance under higher Reidemeister moves coming from the codimension-two singularities of plane curves. We show that they represent genuinely new 1-cohomology classes and compute their pairings with the rotation, rolling, half rolling, bracket and half bracket loops. A key new feature is that β1β_1 and β2β_2 can pair nontrivially with bracket and half-bracket loops. We conjecture that (α3<sup>1,β1,β2)(α_3<sup>1,β_1,β_2) over Q\mathbb{Q}, and their mod 2 reductions together with β3β_3 over Z/2Z\mathbb{Z}/2\mathbb{Z}, form bases of degree-one cohomology up to order 4 in the sense of Vassiliev. In addition, we show that the reparametrization loop is homotopic to the rolling loop concatenated with the rotation loop in Emb⁡(S<sup>1,</sup>S<sup>3)\operatorname{Emb}(S<sup>1,</sup> S<sup>3). Finally, we give the criteria for a 1-cohomology class in the long knot space to descend to 1-cohomology classes in Emb⁡(S<sup>1,</sup>S<sup>3)\operatorname{Emb}(S<sup>1,</sup> S<sup>3) and Emb⁡(S<sup>1,</sup>S<sup>3)/Diff⁡<sup>+(S<sup>1)\operatorname{Emb}(S<sup>1,</sup> S<sup>3)/\operatorname{Diff}<sup>{+}(S<sup>1). Using these criteria, we show that β1β_1 descends to a nontrivial 1-cohomology class in Emb⁡(S<sup>1,S<sup>3)\operatorname{Emb}(S<sup>1,S<sup>3), while β1 mod 2β_1 \bmod 2 and β3β_3 descend to linearly independent nontrivial 1-cohomology classes in Emb⁡(S<sup>1,</sup>S<sup>3)/Diff⁡<sup>+(S<sup>1)\operatorname{Emb}(S<sup>1,</sup> S<sup>3)/\operatorname{Diff}<sup>{+}(S<sup>1).

Authors (1)

Summary

No one has generated a summary of this paper yet.

Paper to Video (Beta)

No one has generated a video about this paper yet.

Whiteboard

No one has generated a whiteboard explanation for this paper yet.

Continue Learning

We haven't generated follow-up questions for this paper yet.

Tweets

Sign up for free to view the 1 tweet with 0 likes about this paper.