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Fractional Hardy--Maz'ya inequality on a half-space

Published 9 Sep 2026 in math.AP and math.FA | (2609.10832v1)

Abstract: The main purpose of this article is to provide a fractional counterpart of the well-known Maz'ya inequality on the half-space, that is R<sup>d<em>+</em>R<sup>d<em>+u(x)u(y)<sup>pxy<sup>d+spdydxD</sup></sup></em>d,s,pR<sup>d<em>+u(x)<sup>pxd<sup>spdx+C</sup></sup></em>d,s,p,τR<sup>d<em>+u(x)<sup>px</sup></em>d<sup>spτ(xd1<sup>2+xd<sup>2)<sup>τ/2dx,</sup></sup></sup></sup></sup></sup></sup></sup> \int_{\mathbb{R}<sup>{d}<em>{+}}\int</em>{\mathbb{R}<sup>{d}<em>{+}}\frac{|u(x)-u(y)|<sup>p}{|x-y|<sup>{d+sp}}dy\,dx\ge\mathcal{D}</sup></sup></em>{d,s,p}\int_{\mathbb{R}<sup>{d}<em>{+}}\frac{|u(x)|<sup>p}{x_d<sup>{sp}}dx+C</sup></sup></em>{d,s,p,τ}\int_{\mathbb{R}<sup>{d}<em>{+}}\frac{|u(x)|<sup>p}{x</sup></em>{d}<sup>{sp-τ}\left(x_{d-1}<sup>2+x_d<sup>2\right)<sup>{τ/2}}dx,</sup></sup></sup></sup></sup></sup></sup></sup> where D<em>d,s,p\mathcal{D}<em>{d,s,p} stands for the sharp constant in the fractional Hardy inequality on a half-space R<sup>d</sup></em>+\mathbb{R}<sup>{d}</sup></em>{+}. We also obtain a similar result in the setting of Sobolev--Bregman forms.

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