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Latin Squares with Few Transversals

Published 8 Sep 2026 in math.CO | (2609.08624v1)

Abstract: Let t(n)t(n) denote the minimum number of transversals in a Latin square of odd order nn. Improving upon a recent bound of Dai, Divoux and Kelly, we prove that for every nn such that n≡3(mod6)n \equiv 3 \pmod 6, [ t(n) \leq \left( \left(1+o(1)\right) \frac{2n}{3e2}\right)n. ] Our proof is based on a family of 3×33 \times 3 block Latin squares whose transversals are constrained to either lie entirely in the diagonal blocks or avoid them altogether.

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