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Ten Squares Force an Overlap

Published 27 May 2026 in math.CO, cs.DM, and cs.FL | (2605.28570v1)

Abstract: We prove that every concatenation of $10$ or more binary squares contains an overlap. The bound $10$ is best possible. In contrast, over a ternary alphabet, there are infinitely long overlap-free words that consist of a concatenation of squares.

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