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On a conjecture of λλ-Aluthge transforms and Hilbert--Schmidt self-commutators

Published 4 Mar 2026 in math.FA | (2603.04655v1)

Abstract: Let AA be a complex square matrix, and write its polar decomposition as A=UAA=U|A|. For $0<λ<1$, the λλ-Aluthge transform of AA is defined by Δ<em>λ(A)=A<sup>λUA<sup>1λ.</sup></sup> Δ<em>λ(A)=|A|<sup>λU|A|<sup>{1-λ}.</sup></sup> In 2007, Huang and Tam conjectured that the Frobenius norm of the self-commutator is contractive under Δ</em>λΔ</em>λ: for every $0<λ<1$, A<sup><em>AAA</em>F</sup>  Δ<em>λ(A)<sup>Δ</sup></em>λ(A)Δ<em>λ(A)Δ</em>λ(A)<sup>F.</sup> |A<sup><em>A-AA^</em>|_{F}</sup> \ \ge\ |Δ<em>λ(A)<sup>*Δ</sup></em>λ(A)-Δ<em>λ(A)Δ</em>λ(A)<sup>*|_{F}.</sup> If this inequality held, then the iterated self-commutator norms $$ \Bigl{\bigl|Δ<em>λ<sup>{\,m}(A)<sup>*Δ</sup></sup></em>λ<sup>{\,m}(A)</sup> -Δ<em>λ<sup>{\,m}(A)Δ</sup></em>λ<sup>{\,m}(A)<sup>*\bigr|<em>F\Bigr}</em>{m\in\mathbb</sup></sup> N} $$ would form a nonincreasing sequence and necessarily converge to $0$. In this paper we provide a counterexample, thereby disproving the conjecture. We also obtain the quantitative bounds $$ \sqrt{\frac32}\ \le\ \sup_{\substack{A\in\mathbb{M}<em>n(\mathbb{C}),\ A<sup>*A\neq</sup> AA<sup>*\</sup> 0&lt;λ&lt;1}} \frac{|Δ</em>λ(A)<sup><em>Δ<em>λ(A)-Δ</em>λ(A)Δ_λ(A)^</em>|_F}{|A<sup><em>A-AA^</em>|_F}</sup></sup> \ \le\ 2. $$

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