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On Sidon sets with squares, cubes and quartics in short intervals

Published 9 Feb 2026 in math.NT | (2602.08807v1)

Abstract: Representative examples of our results are as follows. For any positive integer NN the equation x<sup>3+y<sup>3=z<sup>3+t<sup>3,</sup></sup></sup></sup>x,y,z,t∈N,x,y≠z,t x<sup>3+y<sup>3=z<sup>3+t<sup>3,</sup></sup></sup></sup> \quad x,y,z,t\in \mathbb{N}, \quad {x,y}\not={z,t} has no solutions satisfying $$ N\le x,y,z,t &lt; N+\Bigl(\frac{38}{3}N+\frac{1297}{36}\Bigr)<sup>{1/2}+\frac{19}{6}.</sup> $$ The strict inequality $&lt;$" can not be substituted by≤\le", that is, there exist infinitely many positive integers NN such that the equation has a solution with N≤x,y,z,t≤N+(383N+129736)<sup>1/2+196.</sup> N\le x,y,z,t \le N+\Bigl(\frac{38}{3}N+\frac{1297}{36}\Bigr)<sup>{1/2}+\frac{19}{6}.</sup> There is an absolute constant $c&gt;0$ such that for any positive integer NN the equation has a solution satisfying N≤x,y,z,t≤N+cN<sup>2/3.</sup> N\le x,y,z,t \le N+cN<sup>{2/3}.</sup> For any $\varepsilon&gt;0$ there exist infinitely many positive integers NN such that the equation has no solutions satisfying N≤x,y,z,t≤N+N<sup>4/7−ε.</sup> N\le x,y,z,t \le N+N<sup>{4/7-\varepsilon}.</sup> There is an absolute constant $c&gt;0$ such that for any positive integer NN the equation x<sup>4+y<sup>4=z<sup>4+t<sup>4,</sup></sup></sup></sup>x,y,z,t∈N,x,y≠z,t, x<sup>4+y<sup>4=z<sup>4+t<sup>4,\quad</sup></sup></sup></sup> x,y,z,t\in\mathbb{N}, \quad {x,y}\not={z,t}, has no solutions satisfying N≤x,y,z,t≤N+cN<sup>3/5.</sup> N\le x,y,z,t \le N+cN<sup>{3/5}.</sup> There is an absolute constant $c&gt;0$ such that for any positive integer NN this equation has a solution satisfying N≤x,y,z,t≤N+cN<sup>12/13.</sup> N\le x,y,z,t \le N+cN<sup>{12/13}.</sup>

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