Bounded ribbonlength for knot families and multi-twist Möbius bands

Abstract: Take a thin, rectangular strip of paper, add in an odd number of half-twists, then join the ends together. This gives a multi-twist paper M\"obius band. We prove that any multi-twist paper M\"obius band can be constructed so the aspect ratio of the rectangle is $3\sqrt{3}+\epsilon$ for any $\epsilon>0$. We could also take the thin, rectangular strip of paper and tie a knot in it, then join the ends and fold flat in the plane. This creates a folded ribbon knot. We apply the techniques used to prove the multi-twist paper M\"obius band result to $(2,q)$ torus knots and twist knots. We prove that any $(2,q)$-torus knot can be constructed so that the folded ribbonlength $\leq 13.86$. We prove that any twist knot can be constructed so that the folded ribbonlength is $\leq 17.59$. Both of these results give the lower bound for the ribbonlength crossing number problem which relates the infimal folded ribbonlength of a knot type $[K]$ to its crossing number $\text{Cr}(K)$. That is, we have shown $\alpha=0$ in the equation $$c\cdot \text{Cr}(K)^\alpha \leq \text{Rib}([K])$$, where $c$ is a constant.