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Invariance of three-dimensional Bessel bridges in terms of time reversal

Published 10 Mar 2025 in math.PR | (2503.06813v2)

Abstract: Given $a,b\ge 0$ and $t>0$, let $\rho ={ \rho {s}} _{0\le s\le t}$ be a three-dimensional Bessel bridge from $a$ to $b$ over $[0,t]$. In this paper, based on a conditional identity in law between Brownian bridges stemming from Pitman's theorem, we show in particular that the process given by \begin{align*} \rho _{s}+\Bigl| b-a+ \min _{0\le u\le s}\rho _{u}-\min _{s\le u\le t}\rho _{u} \Bigr| -\Bigl| \min _{0\le u\le s}\rho _{u}-\min _{s\le u\le t}\rho _{u} \Bigr| ,\quad 0\le s\le t, \end{align*} has the same law as the time reversal ${ \rho _{t-s}} _{0\le s\le t}$ of $\rho $. As an immediate application, letting $R={ R{s}} {s\ge 0}$ be a three-dimensional Bessel process starting from $a$, we obtain the following time-reversal and time-inversion results on $R$: ${ R{t-s}} {0\le s\le t}$ is identical in law with the process given by \begin{align*} R{s}+R_{t}-2\min {s\le u\le t}R{u},\quad 0\le s\le t, \end{align*} when $a=0$, and ${ sR_{1/s}} {s>0}$ is identical in law with the process given by \begin{align*} R{s}-2(1+s)\min {0\le u\le s}\frac{R{u}}{1+u}+a(1+s),\quad s>0, \end{align*} for every $a\ge 0$.

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