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Galois module structure of algebraic integers of the simplest cubic field

Published 15 May 2023 in math.NT | (2305.08888v3)

Abstract: Let LnL_n be a simplest cubic field with Galois group G=Gal(Ln/Q)G=\rm{Gal} (L_n/\mathbb Q). The associated order is denoted as A<em>Ln/Q:=x∈Q[G] ∣ x⋅O</em>Ln⊂O<em>Ln{\cal A}<em>{L_n/\mathbb Q}:= { x\in {\mathbb Q} [G] \, |\, x \cdot \cal{O}</em>{L_n} \subset {\cal O}<em>{L_n } }, where O</em>Ln{\cal O}</em>{L_n} is the ring of integers of LnL_n. Leopoldt showed that O<em>Ln≃A</em>Ln/Q\cal{O}<em>{L_n} \simeq {\cal A}</em>{L_n/\mathbb Q} as A<em>Ln/Q{\cal A}<em>{L_n/\mathbb Q}-modules. In this paper, we give a generator of the A</em>Ln/Q{\cal A}</em>{L_n/\mathbb Q}-module O<em>Ln{\cal O}<em>{L_n} explicitly using the roots of Shanks' cubic polynomial. If Ln/QL_n/\mathbb Q is tamely ramified, then we have A</em>Ln/Q=Z[G]{\cal A}</em>{L_n/\mathbb Q}=\mathbb Z [G], and the conjugates form a normal integral basis, which has been obtained explicitly in the previous work of Hashimoto and the second author.

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