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On λλ-homomorphic skew braces

Published 12 Apr 2020 in math.RA | (2004.05555v1)

Abstract: For a skew left brace (G,,)(G, \cdot, \circ), the map λ:(G,)Aut  (G,),  aλa\lambda : (G, \circ) \to \mathrm{Aut} \;(G, \cdot),~~a \mapsto \lambda_a, where λa(b)=a<sup>1</sup>(ab)\lambda_a(b) = a<sup>{-1}</sup> \cdot (a \circ b) for all a,bGa, b \in G, is a group homomorphism. Then λ\lambda can also be viewed as a map from (G,)(G, \cdot) to Aut  (G,)\mathrm{Aut}\; (G, \cdot), which, in general, may not be a homomorphism. We study skew left braces (G,,)(G, \cdot, \circ) for which λ:(G,)Aut  (G,)\lambda : (G, \cdot) \to \mathrm{Aut}\; (G, \cdot) is a homomorphism. Such skew left braces will be called λ\lambda-homomorphic. We formulate necessary and sufficient conditions under which a given homomorphism λ:(G,)Aut  (G,)\lambda : (G, \cdot) \to \mathrm{Aut}\; (G, \cdot) gives rise to a skew left brace, which, indeed, is λ\lambda-homomorphic. As an application, we construct skew left braces when (G,)(G, \cdot) is either a free group or a free abelian group. We prove that any λ\lambda-homomorphic skew left brace is an extension of a trivial skew brace by a trivial skew brace. Special emphasis is given on λ\lambda-homomorphic skew left brace for which the image of λ\lambda is cyclic. A complete characterization of such skew left braces on the free abelian group of rank two is obtained.

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