Free arrangements with low exponents

Published 22 Jul 2017 in math.CO | (1707.07091v4)

Abstract: In this article we show that any free hyperplane arrangement with exponents 1's and 2's is a supersolvable arrangement. We conjecture that any free arrangement with exponents 1's, 2's and exactly one 3, is also supersolvable, and we show this conjecture for hyperplane arrangements of ranks 4 and 5, and for inductively free arrangements of any rank.

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Stefan O. Tohaneanu

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