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Symmetry and spontaneous symmetry breaking of the Hubbard model on a square lattice ground state

Published 24 Mar 2010 in cond-mat.str-el | (1003.4619v2)

Abstract: In this paper we consider the simplified form that a recently introduced general operator description of the Hubbard model on the square lattice with Na<sup>2≫</sup>1N_a<sup>2\gg</sup> 1 sites, effective transfer integral tt, and onsite repulsion UU has in a suitable one- and two-electron subspace. Such an operator description is that consistent with the model exact global symmetry recently extended to SO(3)×SO(3)×U(1)SO(3)\times SO(3)\times U(1). There is a large consensus that in the thermodynamic limit Na<sup>2→∞N_a<sup>2\rightarrow\infty long-range antiferromagnetic order occurs in the spin-density m=0m=0 ground state of the half-filled Hubbard model on the square lattice. Here we find that the corresponding spontaneous symmetry breaking lowers the symmetry of such a state from SO(3)×SO(3)×U(1)SO(3)\times SO(3)\times U(1) for Na<sup>2≫</sup>1N_a<sup>2\gg</sup> 1 large but finite to [U(2)×U(1)]/Z2<sup>2</sup>≡[SO(3)×U(1)×U(1)]/Z2[U(2)\times U(1)]/Z_2<sup>2</sup> \equiv [SO(3)\times U(1)\times U(1)]/Z_2 for Na<sup>2→∞N_a<sup>2\rightarrow\infty. Moreover, we argue that the spin effective lattice being identical to the original lattice is a necessary condition for the occurrence of ground-state long-range antiferromagnetic order in the limit Na<sup>2→∞N_a<sup>2\rightarrow\infty. Consistently, strong evidence is provided that for very small hole concentration $0&lt;x\ll1$ the ground state has a short-range incommensurate-spiral spin order. Our results are of interest both for condensed-matter systems and ultra-cold fermionic atoms on an optical square lattice.

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