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A classification of sharp tridiagonal pairs

Published 12 Jan 2010 in math.RA and math.CO | (1001.1812v1)

Abstract: Let $F$ denote a field and let $V$ denote a vector space over $F$ with finite positive dimension. We consider a pair of linear transformations $A:V \to V$ and $A*:V \to V$ that satisfy the following conditions: (i) each of $A,A*$ is diagonalizable; (ii) there exists an ordering $\lbrace V_i\rbrace_{i=0}d$ of the eigenspaces of $A$ such that $A* V_i \subseteq V_{i-1} + V_{i} + V_{i+1}$ for $0 \leq i \leq d$, where $V_{-1}=0$ and $V_{d+1}=0$; (iii) there exists an ordering $\lbrace V*i\rbrace{i=0}\delta$ of the eigenspaces of $A*$ such that $A V*_i \subseteq V*_{i-1} + V*_{i} + V*_{i+1}$ for $0 \leq i \leq \delta$, where $V*_{-1}=0$ and $V*_{\delta+1}=0$; (iv) there is no subspace $W$ of $V$ such that $AW \subseteq W$, $A* W \subseteq W$, $W \neq 0$, $W \neq V$. We call such a pair a {\it tridiagonal pair} on $V$. It is known that $d=\delta$ and for $ 0 \leq i \leq d$ the dimensions of $V_i,V_{d-i},V*_i, V*_{d-i}$ coincide. The pair $A,A*$ is called {\it sharp} whenever ${\rm dim} V_0=1$. It is known that if $F$ is algebraically closed then $A,A*$ is sharp. In this paper we classify up to isomorphism the sharp tridiagonal pairs. As a corollary, we classify up to isomorphism the tridiagonal pairs over an algebraically closed field. We obtain these classifications by proving the $\mu$-conjecture.

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