Tiling by the ideal right-angled octahedron
Prove that every ideal, right-angled polyhedron assembled from copies of the Scharlau–Walhorn polyhedron SW#1{2} is tiled by the ideal, right-angled hyperbolic octahedron.
References
We conclude with a formal statement of the conjecture mentioned after Thm. {Thm:MainConverse}: Let $\cP$ be the polyhedron SW#1{2}, and let $\cO$ be the ideal, right-angled hyperbolic octahedron. Then any ideal, right-angled $\cP$-polyhedron is tiled by~$\cO$.
— Arithmetic Polyhedra
(2609.05349 - Allcock et al., 4 Sep 2026) in Conjecture 5.?, Section 5, subsection “The case SW#1{2}”; reiterated in Section 6, Further Directions, item 1