Sign of the real part of superfluid stiffness at μ=0 when Re(Δ̄Δ) ≤ 0
Determine, for the isotropic three-dimensional BCS-type non-Hermitian superconductor with constant s-wave pairing mean fields Δ and \bar{Δ} (not constrained to be Hermitian conjugates) at zero chemical potential μ=0, whether the real part of the superfluid stiffness Q is positive or negative when Re(\bar{Δ}Δ) ≤ 0, where Q is defined as the second derivative of the action with respect to the vector potential evaluated at zero field.
Sponsor
References
If $\Re[\bar{\Delta}\Delta]\leq 0$, there is an interplay of terms under integral over $\omega$ and the outcome is not known in general.
— Meissner effect in non-Hermitian superconductors
(2410.07853 - Tamura et al., 10 Oct 2024) in Main text, Calculation of superfluid stiffness, paragraph below Eq. (10)