Sharpness of the 2/(d+2) exponent in the W1–MSW1 comparison
Determine whether the exponent 2/(d+2) in the inequality comparing the 1‑Wasserstein distance W1(μ,ν) and the max‑sliced distance MSW1(μ,ν) for probability measures supported on a ball in ℝ^d, namely W1(μ,ν) ≲ R^{d/(d+2)} MSW1(μ,ν)^{2/(d+2)}, is optimal. Precisely, prove or refute that the exponent 2/(d+2) is sharp in general (beyond the known asymptotic lower bound 2/d).
References
Whether the exponent \frac{2}{d+2} is sharp in eq:sliced-comparison-bobkov is not known but it is at least asymptotically sharp since also explains why in eq:sliced-comparison-bobkov the exponent cannot be better than \frac{2}{d}.
— Sharp comparisons between sliced and standard $1$-Wasserstein distances
(2510.16465 - Carlier et al., 18 Oct 2025) in Introduction (discussion around equation (1.3))