Conjectural divisibility for the non-split recurrence example
Determine whether, for the sequence defined by f_{n+1}=\frac{1}{n^2+1}\sum_{k=0}^{n}f_kf_{n-k} with f_0=1, the product \prod_{k=0}^{\lfloor n/2\rfloor}(k^2+1) divides 2^n d_n for every n≥0, where d_n is the denominator of f_n.
References
Moreover, it seems that ∏⌊n/2⌋k=0 (k2 + 1) divides 2ndn for all n ≥ 0. If true, this conjecturally implies that there exist no integers δ, ν, μ, s ≥ 0 such that dn divides δn+1(νn + μ)!sfor all n ≥ 0.
— Arithmetic properties of the Taylor coefficients of differentially algebraic power series
(2502.09259 - Krattenthaler et al., 13 Feb 2025) in Section 3.9, page 24