Subspace property of the nilpotentizer

Determine whether the nilpotentizer \(nil(L)=\{x\in L\mid \langle h,x\rangle\text{ is nilpotent for every }h\in L\}\) is a subspace for every finite-dimensional Lie algebra \(L\).

Background

The nilpotentizer nil(L)nil(L) is defined as the set of elements that generate a nilpotent subalgebra with every element of the Lie algebra. Earlier results establish inclusions such as nil(L)E(L)nil(L)\subseteq E(L) and identify nil(L)nil(L) with the hypercenter in characteristic zero, but they do not establish that nil(L)nil(L) is closed under addition and scalar multiplication in arbitrary characteristic.

The question asks for a general structural characterization of this set, specifically whether it always has the linear-subspace structure naturally suggested by its definition.

References

Is $nil(L)$ always a subspace?

The nilpotent graph of a finite0-dimensional Lie algebra  (2506.19758 - Towers et al., 24 Jun 2025) in Questions following the definition and example of the non-nilpotent graph, Section 5