Lower bound for strong nodal domains at the top eigenvalue of ternary Hamming graphs
Prove that every eigenfunction f of the Hamming graph H(n, 3) with Laplacian eigenvalue 3n has at least n + 1 strong nodal domains.
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In other words, the last remaining open case for q ≥ 3 is q = 3 and i = n. In our opinion, this case has something in common with the case q = 2, i = n − 1, and the minimum number of strong nodal domains seems to be a linear on n function. In particular, we conducted numerical experiments for n = 2, 3, 4, i = n and the functions with minimum number of strong nodal domains that we found have 3, 4 and 5 strong nodal domains respectively (see Figure 1). Based on these computations, we formulate the following conjecture. Conjecture 2. For any eigenfunction f of H(n, 3), n ≥ 1, with eigenvalue 3n we have SND(f ) ≥ n + 1.