Lower bound for the functional volume product among s-concave functions with g^s in F (s<0)
Determine, for every integer n ≥ 1 and s ∈ (−1/n, 0), whether for any even function g: R^n → [0,∞) with g^s ∈ F the lower bound ∫_{R^n} g(x) dx · ∫_{R^n} L_s g(y) dy ≥ (1/(1+ns)) · 4^n / ((1+s)(1+2s)···(1+ns)) holds, with equality for g(x) = (max(1, ||x||_∞))^{1/s}. Here F denotes the class of convex lower semi-continuous functions f: R^n → (0,∞) such that for any x ≠ 0, lim_{t→∞} f(tx) = ∞ and t ↦ f(tx)/t is non-increasing on (0,∞), and L_s g is the s-polar defined by L_s g(y) = inf_{x: g(x)>0} [(1 − s⟨x,y⟩)_+^{1/s} / g(x)].
References
As we shall see from the one-dimensional case, it is natural to formulate two more conjectures from which Conjecture \ref{mahler-s} follows in the case s<0. The first one postulates a sharp lower bound on the functional volume product of s-concave even functions, among the ones such that gs∈F. Conjecture Let s∈(−\frac{1}{n},0) and let g:R{n}→R_{+} be even such that gs∈F. Then, $$ \int_{R{n}} g(x) dx \int_{R{n}} L_{s} g(y) dy \geq \frac{1}{(1+ns)}\times\frac{4{n}}{(1+s)\cdots(1+ns)}, $$ with equality for g(x)=(\max(1,|x|_\infty)){1/s}.