Liu–Mesnager–Chen upper-bound conjecture for distance to affine functions
Prove or refute that every map f:GF(2)^n\to GF(2)^m satisfies A_f\leq (1-2^{-m})(2^n-2^{n/2}), and, in the case n=m, that A_f\leq 2^n-2^{n/2}-1.
References
In 2017, Liu, Mesnager and Chen formulated a conjecture: For any map f:GF{2}n\to GF{2}m, A_f\leq \left(1-\frac{1}{2m}\right)\big(2n-2{n/2}\big) holds. In particular, if n=m, then A_f\leq 2n-2{n/2}-1.
— On the minimum Hamming distance between vectorial Boolean and affine functions
(2503.03905 - Nagy, 5 Mar 2025) in Section 1, Introduction, Problem (Liu-Mesnager-Chen Conjecture)