Establish full rank of the symmetric-power Frobenius
Prove that the Frobenius operator \(\bar{\beta}_{k,a}\) has full rank on the first cohomology space \(H^1(\mathcal{S}_k,\nabla)\), thereby establishing equality in the degree bound for \(L({\rm Sym}^{k}Kl_{n,m}/\mathbb{F}_q,T)\).
References
Our main result asserts only the degree of L({\rm Sym}{k}Kl_{n,m}/\mathbb{F}_{q},T) is at most \frac{m}{mn+1}\binom{nm+k}{k}, since we are unable to prove \bar{\beta}_{k,a} has full rank on H1 (\mathcal{S}_k , \nabla).
However, as in the case Kl_{n,1} studied in , it is reasonable to predict the degree of the rational function L({\rm Sym}{k}Kl_{n,m}/\mathbb{F}_{q},T)(degree of the numerator subtract the degree of the denominator) is $$\frac{m}{mn+1}\left(\binom{mn+k}{k}-d_{k}(n,m,p)\right)$$ given that p\nmid m(mn+1).