Cusick Conjecture: Binary Sum-of-Digits
- Cusick Conjecture is a statement about the binary sum-of-digits function under translation, asserting that cₜ > ½ for every nonnegative integer t.
- It offers equivalent formulations that connect carry propagation in binary addition, valuations of rising factorials, and properties of binomial coefficients.
- Recent proofs using analytic, combinatorial, and probabilistic methods provide explicit lower bounds such as cₜ ≥ ½ + 2^(–2s₂(t)–1), confirming the conjecture for all t ≥ 1.
The Cusick conjecture is a statement about the binary sum-of-digits function under translation. For a nonnegative integer , let denote the number of $1$'s in the base-$2$ expansion of , and define
where the limit exists. T. W. Cusick conjectured that for every . The conjecture connects carry propagation in binary addition, valuations of rising factorials and binomial coefficients, and asymptotic densities for digital functions. A partial resolution showed that for in a set of asymptotic density 0, and a later first-exit argument proved the conjecture in full with the explicit bound
1
for every 2 (Drmota et al., 2015, Cheng, 22 Jun 2026).
1. Definitions and basic distributions
Let
3
and define
4
For each fixed 5, the central density is
6
A closely related quantity is
7
A finer distribution is obtained by recording the exact digit-sum difference. One introduces
8
or equivalently, in later notation,
9
These densities define probability measures on $1$0; in the $1$1 formulation they have mean zero. The tails recover the main quantities: $1$2
The distributions satisfy binary dilation and odd-step recurrences. In the $1$3-notation,
$1$4
In the $1$5-notation,
$1$6
These recurrences are the basic structural relations underlying most later work (Drmota et al., 2015, Tarłowski, 9 May 2026).
2. Equivalent formulations
A striking feature of the conjecture is that it admits several equivalent formulations.
The first is in terms of carry-counting in binary addition. If $1$7 denotes the exponent of $1$8 dividing $1$9, and
$2$0
is the rising factorial, then
$2$1
Hence
$2$2
Because $2$3 is periodic of period $2$4, the density $2$5 can be interpreted through the zero set of a polynomial modulo a power of $2$6.
A second formulation uses Pascal’s triangle. From Legendre’s formula $2$7, one obtains
$2$8
Thus
$2$9
Equivalently,
0
has fewer than 1 zeros modulo 2.
These reformulations place the conjecture simultaneously in the theory of digital sums, 3-adic valuations, and arithmetic properties of binomial coefficients and polynomial congruences (Drmota et al., 2015).
3. The density-one theorem and analytic-combinatorial proof
The first major progress was obtained by Drmota, Kauers, and Spiegelhofer. Their main theorem states that for any 4, as 5,
6
In particular, the set of 7 for which 8 has asymptotic density 9. Simultaneously, 0 on a set of density 1.
The proof begins with dyadic blocks 2. Writing
3
one obtains an explicit formula for 4 by unfolding the recurrences. Summing over 5 yields the first-moment asymptotics
6
and similarly
7
The second moment is handled through a trivariate generating function. With
8
one defines
9
and the recurrences imply that 0 is an explicit rational function. The mean of 1 over the same dyadic block becomes a diagonal coefficient of
2
Multivariate complex-analytic saddle-point methods in the sense of Pemantle–Wilson, or alternatively a guessed and checked univariate 3-finite recurrence, then give
4
with an analogous formula for 5.
At that point Chebyshev’s inequality supplies concentration: 6 while
7
so most 8 satisfy 9. Summing over 0 gives the density-one conclusion. The same paper also exhibited the explicit sequence
1
for which
2
hence 3 for all 4 (Drmota et al., 2015).
4. Quantitative lower bounds, almost-sure results, and numerical evidence
Later work refined the density-one picture. Spiegelhofer proved that for every 5 there exists 6 such that whenever the binary expansion of 7 contains at least 8 blocks of consecutive 9's, one has
0
As a corollary, there are constants 1, depending on 2, such that for all 3,
4
This replaced earlier exceptional-set bounds of size 5 by an effective 6 estimate.
The proof uses the characteristic function
7
together with the identity
8
A moment-generating function 9 satisfies the same two-scale recurrences as the underlying distributions, and bounds for its moments depend polynomially on the number of blocks of 0's in the binary expansion of 1. A matrix-product representation for 2 yields the estimate
3
when 4 is the number of such blocks and 5 is away from 6. Near 7, Taylor expansion and moment bounds control the integral (Spiegelhofer, 2019).
The same paper records numerical evidence: a computer check for all 8 verified 9, with minimal value approximately 00 at
01
and its digit-reverse (Spiegelhofer, 2019).
A related almost-sure phenomenon arises from the Tu–Deng conjecture. For
02
Spiegelhofer and Wallner proved that for every 03, the proportion of 04 with
05
tends to 06 as 07. They also proved that the Tu–Deng conjecture implies Cusick’s conjecture, thereby linking two distinct binary digit-sum problems (Spiegelhofer et al., 2017).
5. Martingales, binary trees, and stopped random walks
A different structural approach reinterprets the measures 08 through non-autonomous dynamics on probability measures. Restricting first to odd indices, one introduces the maps
09
and a partial order on odd integers generated by finite sequences of left and right steps. In this framework one works with centered measures 10 defined by
11
together with the recurrences
12
For an infinite word 13, the pair 14 evolves under the non-autonomous maps
15
The same recursion can be encoded by planar binary trees 16. To each finite tree one associates a stopping time 17 for the simple symmetric random walk 18, and the law of the stopped position 19 is exactly 20.
This representation yields explicit structural information. If 21 contains 22 letters 23 and 24 letters 25, then
26
and the two extreme atoms have masses 27 and 28. The symmetries
29
hold, where 30 exchanges 31 and 32 reverses the word. Variance is monotone with respect to the partial order: 33 implies 34. Among words of fixed length, the constant words 35 minimize the variance, with
36
while the alternating word 37 maximizes it, with
38
This framework leads to a median-preserving formulation. The original conjecture follows once one proves
39
A stronger conjecture proposed in this setting is
40
for every finite word 41. Numerically, a search among odd 42 found that the global minima of 43 are exactly 44, and that those minimizers always end in the letter 45; no counterexample to the stronger inequality 46 was found up to that range (Tarłowski, 9 May 2026).
6. Full proof and explicit lower bound
The full conjecture was proved by a first-exit argument based on exact deconvolution. The starting point is the identity
47
where 48 is finitely supported and satisfies
49
The initial measure is explicit: 50
The deconvolution kernel 51 is realized as the law of a stopped simple random walk. For a finite binary word 52, let 53 be the set of subsequences of 54, and let
55
for i.i.d. Bernoulli56 variables 57. If
58
then
59
for the corresponding odd integer 60.
The proof then establishes a general median theorem for any finite subsequence order ideal 61: 62 is a two-sided median of the stopped walk,
63
For principal ideals 64, a marked-deletion versus marked-insertion argument yields a strict quantitative bias. If 65, 66, and
67
then
68
A final support-cutoff argument transfers this strict bias from the kernel 69 back to the original measures 70. The resulting theorem is
71
In particular, 72 for every 73, proving Cusick’s conjecture. The same work emphasizes that the proof uses elementary properties of binary digits, simple random walks, and finite combinatorics of subsequences, and notes that analogous questions for bases 74 remain open (Cheng, 22 Jun 2026).