Papers
Topics
Authors
Recent
Assistant
AI Research Assistant
Well-researched responses based on relevant abstracts and paper content.
Custom Instructions Pro
Preferences or requirements that you'd like Emergent Mind to consider when generating responses.
Gemini 2.5 Flash
Gemini 2.5 Flash 149 tok/s
Gemini 2.5 Pro 46 tok/s Pro
GPT-5 Medium 25 tok/s Pro
GPT-5 High 30 tok/s Pro
GPT-4o 112 tok/s Pro
Kimi K2 205 tok/s Pro
GPT OSS 120B 434 tok/s Pro
Claude Sonnet 4.5 38 tok/s Pro
2000 character limit reached

Unique polynomial solution of $m/n=1/x+1/y+1/z$ for $n \equiv b {\rm mod}\, a$ if $(a,m)=1$ (2404.01307v1)

Published 3 Mar 2024 in math.GM

Abstract: Necessary and sufficient conditions for the existence of an integer solution of the diophantine equation $m/n=1/x(\lambda)+1/y(\lambda)+1/z(\lambda)$ with $n=b+a\lambda$ are explicitly given for a,b coprime and a not a multiple of m . The solution has the form $x(\lambda)=kn(\lambda)$, $y(\lambda)=n(\lambda)(s+r\lambda)$, $z(\lambda)=(kl/r)(s+r\lambda)$ where parameters $k,l,s,r\in \mathbb{Z}$ obey certain conditions depending on $a,b$. The conditions imply restrictions for some choices of $a,b$ which differ from the ones known in the case $m=4$. E.g., the modulus must be of the form $l(mk-1)$. One can also deduce that primes of the form $1+4K$ are excluded as modulus. Also if $a=p\ne m$ is prime and $b=a+1$, i.e., $n\equiv 1{\rm mod}\, p$, polynomial solutions are shown to be impossible. All results are valid for integers $m \ge 4$.

Summary

We haven't generated a summary for this paper yet.

Dice Question Streamline Icon: https://streamlinehq.com
Lightbulb Streamline Icon: https://streamlinehq.com

Continue Learning

We haven't generated follow-up questions for this paper yet.

Authors (1)

List To Do Tasks Checklist Streamline Icon: https://streamlinehq.com

Collections

Sign up for free to add this paper to one or more collections.

X Twitter Logo Streamline Icon: https://streamlinehq.com

Tweets

This paper has been mentioned in 1 tweet and received 0 likes.

Upgrade to Pro to view all of the tweets about this paper: