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Identities involving Bernoulli and Euler polynomials (1710.07127v1)

Published 19 Oct 2017 in math.CA

Abstract: We present various identities involving the classical Bernoulli and Euler polynomials. Among others, we prove that $$ \sum_{k=0}{[n/4]}(-1)k {n\choose 4k}\frac{B_{n-4k}(z) }{2{6k}} =\frac{1}{2{n+1}}\sum_{k=0}{n} (-1)k \frac{1+ik}{(1+i)k} {n\choose k}{B_{n-k}(2z)} $$ and $$ \sum_{k=1}{n} 2{2k-1} {2n\choose 2k-1} B_{2k-1}(z) = \sum_{k=1}n k \, 2{2k} {2n\choose 2k} E_{2k-1}(z). $$ Applications of our results lead to formulas for Bernoulli and Euler numbers, like, for instance, $$ n E_{n-1} =\sum_{k=1}{[n/2]} \frac{2{2k}-1}{k} (2{2k}-2n){n\choose 2k-1} B_{2k}B_{n-2k}. $$

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