Strictness of the Dimension Inequality for Zeroth de Rham Cohomology

Determine whether the inequality \(\dim_K H^0_{\mathrm{dR}}(A)\le 1+\dim_K H^1(\ker\Phi)\) can be strict for a local Artinian \(K\)-algebra \(A=P/I\), where \(P=K[x_1,\dots,x_n]\), \(\Phi:\Omega^\bullet_{\operatorname{gr}(A)}\to\operatorname{gr}(\Omega_A^\bullet)\) is the canonical filtered differential graded algebra homomorphism, and \(K\) is the base field.

Background

Theorem \ref{thm:ZerothDeRham} establishes the upper bound dim⁡KHdR0(A)≤1+dim⁡KH1(ker⁡Φ)\dim_K H^0_{\mathrm{dR}}(A)\le 1+\dim_K H^1(\ker\Phi), where HdR0(A)=ker⁡(dA)H^0_{\mathrm{dR}}(A)=\ker(d_A) and Φ\Phi compares the de Rham complex of the associated graded ring with the associated graded de Rham complex of AA. The authors report that they found no example in which this inequality is strict, but also no proof that equality always holds. The unresolved task is therefore to decide whether strict inequality can occur for any local Artinian algebra in the stated setting.

References

In spite of extensive efforts, we were not able to find an example in which the inequality in this theorem is strict. On the other hand, we were not able to find a proof of equality either. Therefore we leave it as an open question for future research to decide whether the inequality in this theorem can be strict.

— On the De Rham Cohomology of Zero-Dimensional Schemes  (2609.34819 - Kreuzer et al., 28 Sep 2026) in Section 3.3, immediately after Theorem \ref{thm:ZerothDeRham}