Second-lowest-area minimal surface spanning a great circle
Establish that the minimal surface of second-lowest area in the round three-sphere bounded by a great circle is the Lawson Möbius band \(\overline{\tau}_{1,2}\).
References
While the hemispheres are the simplest minimal surfaces spanning $C$, we expect the Lawson band, $\bar{\tau}_{1,2}$ to be the second simplest:
we expect, by analogy with F. Urbano's theorem , this to characterize $\bar{\tau}_{1,2}$:
If $\Sigma$ is a $C2$ immersion of a Möbius band into $\mathbb{S}3$ that spans $C$, then $$ \mathcal{W}(\Sigma)\geq \mathcal{W}(\bar{\tau}{1,2}) = \mathrm{Area}(\bar{\tau}{1,2}).$$
The area of a non-orientable minimal surface in $\mathbb{S}3$ spanning $C$ with non-zero Euler number is bounded from below by that of an embedded non-orientable minimal surface with index $2$ and boundary $C$.