Determine the optimal exploration-time bound for bounded-underlying-degree temporal graphs
Determine the largest possible exploration time of an always-connected temporal graph on n vertices whose underlying graph has maximum degree at most Δ, thereby closing the polynomial gap between the lower bound Ω(Δ n (1 + log(n/Δ))) and the upper bound O(min{n², n^{3/2}√(Δ log n)}), including the constant-degree case.
References
The two differ by a polynomial factor whenever $\Delta$ is polynomially smaller than $n$, and closing this gap is the main question, open even for constant degree: there the known bounds are $\Omega(n\log n)$ and $O(n{3/2}\sqrt{\log n})$, and our bound does not improve the lower one.
We do not know whether any lower bound with a linear dependence on the degree survives two moves per step.
They conjecture that $O(\sqrt{\Delta_s}\,n)$ steps suffice with high probability when all trees have maximum degree $\Delta_s$.