Montgomery’s ℓ^q conjecture for Dirichlet polynomials
Show that for the Dirichlet polynomial matrix M_Dir with entries (M_Dir)_{t,n} = n^{it} and any q ≥ 2, one has ∥M_Dir∥_{∞→q} ≲ N + N^{1/2} T^{1/q} uniformly for N ≤ T ≤ N^{O(1)}. Equivalently, for any Dirichlet polynomial D(t) = ∑_{n=N}^{2N} b_n e^{it log n} with |b_n| ≤ 1, the inequality ∑_{t=1}^T |D(t)|^q ≲ N^q + N^{q/2} T holds.
References
Conjecture [Montgomery's ℓq conjecture] Suppose N ≤ T ≤ N{O(1)}. For every q ≥ 2, ∥ M_{Dir} ∥_{∞ → q} ≲ N + N{1/2} T{1/q}.
In other words, for any q ≥ 2, if D(t) = ∑_{n=N}{2N} b_n e{i t log n} with |b_n| ≤ 1, then
∑_{t =1}T |D(t)|q ≲ Nq + N{q/2} T.
In more classical language, these computations correspond to the fact that with current understanding of the large values of Dirichlet polynomials, we cannot rule out the scenario that
\left|\sum_{n \sim X{\beta_j}} \frac{a_j(n)}{n{1/2+it}}\right| \geq X{\beta_j(1/2-2/7)}\qquad j=1,2,3
for \gg X{2/7} one-separated points t\in[-X{\tau_1},X{\tau_1}], where a_1(n)=1 and |a_j(n)|\ll d_B(n) for j=2,3 and some fixed B.
In order to obtain the exponent 19/35-\varepsilon in Theorems \ref{thm:intro-mobius}, \ref{thm1.3}, \ref{thm1.4} and \ref{thm1.5}, we would need to essentially have the bound
\int_{X\varepsilon}{X{\tau_1+\varepsilon}}\left|\sum_{n \sim X{1/5}} \frac{1}{n{1/2+it}}\right|5 dt \ll \frac{X{1/2}}{\logA X},
and it is the above-mentioned scenario which prevents us from obtaining this.