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Rule out Pisot-degree-3 powers to establish transcendence of Mills' constant

Show that there does not exist a positive integer m such that Mills' constant ξ_3, defined as the smallest real number ξ > 1 with floor(ξ^{3^k}) prime for every k ∈ N, satisfies that ξ_3^{3^m} is a Pisot number of degree 3. Establishing this would complete the proof that ξ_3 is transcendental.

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Background

The paper proves that for base exponent c ≥ 4 the smallest prime-representing constant ξ_c is transcendental. For c = 3 (Mills’ constant), the main result shows a dichotomy: either ξ_3 is transcendental, or there exists m ∈ N such that ξ_3{3m} is a Pisot number of degree 3.

To conclude transcendence in the c = 3 case, it is therefore sufficient to exclude the latter possibility. The author explains the difficulty of this step in Remark~\ref{Remark-b=3}, where attempting to control the conjugate contributions leads to terms b_k and e_k in the cubic recurrence p_{k+1} = p_k3 − 3 b_k p_k + 3 e_k that resist the methods used for degrees 2 and for c ≥ 4.

References

To prove the transcendency of Mills' constant, it remains to show that there does not exist m\in \mathbb{N} such that \xi{C_{m}} is a Pisot number of degree 3 when b=3.

Mills' constant is irrational (2404.19461 - Saito, 30 Apr 2024) in Remark (labelled Remark~\ref{Remark-b=3}), Section 4