Dice Question Streamline Icon: https://streamlinehq.com

Maximal submodule of V^1(psl_{n|n}) is generated by the singular vector U

Prove that the maximal proper submodule of the universal affine vertex algebra V^1(psl_{n|n}) at level 1 is the submodule U generated by the singular vector $\chi=E^{1,2n-1}_{(-1)}E^{1,2n}_{(-1)}\ket{0}$, and equivalently show that the simple affine quotient satisfies $L_1(psl_{n|n})=V^1(psl_{n|n})/U$.

Information Square Streamline Icon: https://streamlinehq.com

Background

The authors construct a specific singular vector in V1(psl_{n|n}) and the submodule U it generates, use it to constrain the associated variety, and ultimately prove the main geometric result of the paper. They conjecture that U is the maximal proper submodule, which would give a precise structural description of the simple quotient.

They outline potential approaches to proving this conjecture, including inverse quantum Hamiltonian reduction and extending related results in the literature.

References

Before going on to study the associated variety of $psl_{n|n}$, it appears natural to formulate the following conjecture: The maximal proper submodule of $V1(psl_{n|n})$ is $U$. Equivalently $L_1(psl_{n|n}) = V1(psl_{n|n})/U$.

$L_1(\mathfrak{psl}_{n|n})$ from BRST reductions, associated varieties and nilpotent orbits (2409.13028 - Ferrari et al., 19 Sep 2024) in Section 4 (Singular vectors of V^1(psl_{n|n}))