Lower bound on the number of prime factors of 2^{\hat p}-1
Prove or disprove the conjectural lower bound m\geq 2^n for n\geq 3, where m denotes the number of distinct prime factors in the factorization 2^{\hat p}-1=q_1\cdots q_m and \hat p is the product of n distinct primes other than 2 and 3.
References
It is worth mentioning that by taking $n\geq3$, obtaining the minimum value of $m$ may be impossible. By Conjecture 4.3 on page 351 of , they hypothesize, in our context, that for $n\geq3$ we will have $m\geq2n$.
— Constructing solvable groups whose character degree graphs generalize the bowtie
(2608.19374 - Laubacher et al., 19 Aug 2026) in Section 3, final paragraph before the n=3 example