Kaliman–Zaidenberg rigidity conjecture for Pham–Brieskorn rings

Prove the Kaliman–Zaidenberg conjecture that, for a Pham–Brieskorn ring B_{k; a_0,\dots,a_n} over a characteristic-zero field k containing \sqrt{-1}, the ring is non-rigid if and only if some exponent a_i equals 1 or two distinct exponents a_i and a_j both equal 2.

Background

A Pham–Brieskorn ring is the quotient B_{k; a_0,\dots,a_n}=k[x_0,\dots,x_n]/(x_0{a_0}+\cdots+x_n{a_n}). The paper defines rigidity to mean that the only locally nilpotent derivation of the ring is the zero derivation.

The conjecture gives a complete characterization of the non-rigid cases when the base field contains \sqrt{-1}. The implication from the stated exceptional exponent patterns to non-rigidity is proved directly in the survey, and the conjecture is established for n=2 and n=3. The general higher-dimensional case remains unresolved in the paper.

References

In this section we discuss the following conjecture. Let B = B_{; a_0, \dots, a_n} be a Pham-Brieskorn ring and assume (i) \subseteq . Then B_{; a_0, \dots, a_n} is non-rigid if and only if a_i = 1 for some i or a_i = a_j = 2 for some i \neq j.

A Survey on Pham-Brieskorn Varieties  (2609.20149 - Chitayat, 17 Sep 2026) in Section 8, ‘Rigidity’, Conjecture 8.1 (labelled PBConjecture)