Hyper-order versus order for solutions of Hayman’s reduction f′(z) = l1(z)f(z) + h(z)
Determine whether the inequality s(f) ≥ o(h) holds for transcendental meromorphic solutions f(z) of the first-order differential equation f′(z) = l1(z)f(z) + h(z), where l1(z) is a rational function and h(z) is a meromorphic solution of h′(z) = y2(z)h(z) + y3(z) with rational functions y2(z) and y3(z). Here s(f) denotes the hyper-order of f, and o(h) denotes the order of h, both defined via Nevanlinna theory. This inequality is known to hold in special cases (e.g., l1 is a nonzero constant and y3 ≡ 0), but its validity in the general setting remains unresolved.
References
If 1(z) { 0 is a constant and 3(z) =0, then by Theorem 1.1 we have s(f) = o(h). In the general case whether the inequality s(f) ≥ o(h) holds still remains open.
— On the modulus of meromorphic solutions of a first order differential equation
(2407.00580 - Zhang, 30 Jun 2024) in Section 3 (Discussions)