Solve general quadratic form tuple isometry in characteristic two
Determine whether the quadratic form tuple isometry problem over $\mathbb{F}_2$ can be solved in the general case, without the regularity condition required by the previously known algorithm.
References
There is also a different algorithm for quadratic form tuple equivalence in , but that algorithm only works under a regular condition. For example, because of the regular condition, their algorithm does not work with even number of variables. Indeed, an open question in is about the general case of quadratic form tuple isometry.
— Beyond odd characteristic: Faster isomorphism testing of 2-groups of Frattini class 2
(2610.00874 - Grochow et al., 1 Oct 2026) in Section 1, subsection “The significance of 2-groups of Frattini class 2,” footnote following the discussion of the characteristic-two tuple-isometry obstacle