First MAP positions at Fibonacci-number differences
Prove that the first position of a maximum-length MAP in the Fibonacci word satisfies i(F_{2n+1})=F_{2n+3}-2 and i(F_{2n})=F_{4n}-1.
References
Empirical evidence generated by suggests making the following Conjecture \ref{CONJ:idfn}. Unfortunately, because A(F_n) is not eventually constant, as will be shown in the next section, we once again run into the limitation of 's inability to handle the multiplication of two variables. \begin{conj}\label{CONJ:idfn} We have i(F_{2n+1}) = F_{2n+3} - 2, and i(F_{2n})=F_{4n}-1.
— Monochromatic arithmetic progressions in the Fibonacci, Thue-Morse, and Rudin-Shapiro words
(2501.05830 - Joshi et al., 10 Jan 2025) in Section 4.2, subsection “Investigating MAPs in the Fibonacci word in Walnut,” Conjecture 4.8